forked from core/mobile_nebula
Fix state when connection toggle is tapped twice (#16)
Fixes #15. When tapping the toggle in rapid succession, `NebulaVpnService.onStartCommand` is called twice, in serial. This method includes logic to show an error to the user if they somehow attempt to connect to a service while already connected. However, this method of showing an error message (calling `announceExit`) sends a signal to `MainActivity` telling it the service has exited, and that it should set the UI state to "Disconnected." It does not actually disconnect the service at this point, resulting in a state mismatch in which you cannot actually disconnect the service. The solution in this commit is to remove this signalling and simply return out of `onStartCommand` to avoid processing the start request twice if the site is already running.
This commit is contained in:
parent
3123ce5f9a
commit
1d044a1e36
|
@ -50,7 +50,12 @@ class NebulaVpnService : VpnService() {
|
||||||
val id = intent?.getStringExtra("id")
|
val id = intent?.getStringExtra("id")
|
||||||
|
|
||||||
if (running) {
|
if (running) {
|
||||||
|
// if the UI triggers this twice, check if we are already running the requested site. if not, return an error.
|
||||||
|
// otherwise, just ignore the request since we handled it the first time.
|
||||||
|
if (site!!.id != id) {
|
||||||
announceExit(id, "Trying to run nebula but it is already running")
|
announceExit(id, "Trying to run nebula but it is already running")
|
||||||
|
}
|
||||||
|
|
||||||
//TODO: can we signal failure?
|
//TODO: can we signal failure?
|
||||||
return super.onStartCommand(intent, flags, startId)
|
return super.onStartCommand(intent, flags, startId)
|
||||||
}
|
}
|
||||||
|
|
Loading…
Reference in New Issue